H=-4.9t^2+60t+3

Solution for H=-4.9t^2+60t+3 equation:

=-4.9H^2+60H+3

We move all terms to the left:

-(-4.9H^2+60H+3)=0

We get rid of parentheses

4.9H^2-60H-3=0

a = 4.9; b = -60; c = -3;
Δ = b2-4ac
Δ = -602-4·4.9·(-3)
Δ = 3658.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-\sqrt{3658.8}}{2*4.9}=\frac{60-\sqrt{3658.8}}{9.8}
$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+\sqrt{3658.8}}{2*4.9}=\frac{60+\sqrt{3658.8}}{9.8}
$